Rosenlicht unit theorem-II

Recall the theorem (first part) : It says that if X is a k-variety, then U_k(X)=\frac{k[X]^*}{k^*} is a free \mathbb{Z} module of finite rank.

The first step is to be able to say “WLOG, we can assume X is a normal affine k-variety” .

For that, we should know what normalization is. Here’s a very well written post explaining what normalization actually is, with some worked out examples. And in case,the link becomes redundant at some point,  a pdf copy of the same post is here : normalization

Now if Y is any open affine subset of our given X, we construct the normalization of Y, and call it Y '. This is also affine, as the link above explains and k[Y]\hookrightarrow k[Y ']. And since O_X is a sheaf, we have O_X(X)=k[X]\to O_X(Y)\cong k[Y]. In fact this is also injective because X is integral ?

So we have an injective map k[X]\hookrightarrow k[Y'], which induces an injection U_k(X)\hookrightarrow U_k(Y'). Hence if we show the theorem holds for affine normal varieties (like Y’), then because any subgroup of a free \mathbb{Z} finite rank module is also free abelian and of finite rank, we are done !

 

About these ads

About ideallaedi


Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Connecting to %s

Follow

Get every new post delivered to your Inbox.

%d bloggers like this: